Math, asked by singhsaab32, 1 year ago

Find the value of "K"

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Answered by MonarkSingh
2
\huge\red{Answer\: is}

 \frac{(125) {}^{ - 3} }{(25) {}^{ \frac{1}{4} } } = 5 {}^{k} \\ \frac{5 {}^{3 \times ( - 3)} }{5 {}^{2 \times \frac{1}{4} } } = 5 {}^{k} \\ 5 {}^{ - 9- \frac{1}{2} } = 5 {}^{k} \\ 5 {}^{ \frac{ - 19}{2} } = 5 {}^{k} \\ \frac{ - 19}{2} = k
Hope it helps you
Answered by simransahu94
2
(5^3)^-3 ÷ (5^2)^1/4 = 5^k
=> 5^-9 ÷ 5^1/2 = 5^k
=> 5^ -9-1/2 = 5^k
=> 5^ -19/2 = 5^k
so , k = -19/2

simransahu94: plzz mark as brainliest
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