Question

find the value of k
@ x² - (K + 4 )x+ 2K+5=0​

Answer 1

Answer:

+2 and -2

Step-by-step explanation:

Here Determinant is equal to zero

therefoee

b²=4ac

(k+4)²=4*1*2k+5

k²=4

K=+2 and -2

Answer 2

Answer:

k=2

Step-by-step explanation:

If discriminent delta =0

b^2-4ac=0

Where, a=1, b= -(k+4), c=2k+5 in the equation x² - (K + 4 )x+ 2K+5=0

[-(k+4)]^2 - 4(1)(2k+5)=0

(-k-4)^2-4(2k+5)=0

k^2+16+8k-8k-20=0

k^2-4=0

k^2=4

k=√4

k=2

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