7x-2y/xy=5
8x+7y/xy=15
solve this any algebraic method substitution, elimination, Cross multiplication??plz solve this
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Answer:
X = 1 ,y = 1
Step-by-step explanation:
Given simultaneous equations:
(7x-2y)/xy = 5
=> 7x/xy - 2y/xy = 5
=> 7/y - 2/x = 5 ----(1)
and
(8x+7y)/xy = 15
=> 8x/xy + 7y/xy = 15
=> 8/y + 7/x = 15 ----(2)
Let 1/x = a , 1/y = b
Then ,
The equations becomes,
7b-2a=5 -----(3)
8b+7a=15 -----(4)
Now ,
multiply equation (3) by 7, and
equation (4) by 2, we get
49b-14a = 35 ----(5)
16b+14a=30-------(6)
Add equations (5) and (6), we
get
65b = 65
=> b = 65/65
=> b = 1
substitute b=1 in equation (3),
we get
7b - 2 = 5
=> 7b = 5+2
=> b = 7/7
=> b = 1
Therefore,
a = 1 => 1/x = 1 => x = 1
and
b=1 => 1/y = 1 => y = 1
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