Question

Find the value of k by quadratic equations kx(3x-10)+25=0

Answer 1

Hey

Here is your answer,

kx(3x-10)+25=0
3kx^2 - 10kx + 25=0

b^2 - 4ac = (-10k)^2 - 4x3kx25
=100k^2 - 300k
100 k^2 = 300 k
100 k = 300
k = 300/100
k =3

Hope it helps you!

Answer 2

Step-by-step explanation:

kx(3x-10)+25=0

3kx^2 - 10kx + 25=0

b^2 - 4ac = (-10k)^2 - 4x3kx25

=100k^2 - 300k

100 k^2 = 300 k

100 k = 300

k = 300/100

k =3