Question

Find the value of k f(x-1) is a factor of p(x)=x^2+ x+k​

Answer 1

Answer:

-2=K

Step-by-step explanation:

x-1

x=1

p(x)=x×x+x+k=0

=1×1+1+k=0

=1+1 +k=0

= 2 +k=0

= k = -2

●HENCE K= -2.

HOPE IT HELPS YOU....

Answer 2

$Let\: p(x) \:=\: 2x2 + kx$

$Since,\: (x-1) \:is\: a \:factor \:of\: p(x),$

$then \:p(1)\:=\:0$

$2(1)^2 + k(1) \:= \:0$

$⇒ 2+k\: = \:0$

$⇒ k\:= \:-2$

$Hence, \:the\: value \:of \:k \:is\: -2.$