Question

Find the value of k f(x-1) is a factor of p(x)=x^2+ x+k​

Answer 1

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Answer 2

$Let\: p(x) \:=\: 2x2 + kx$

$Since,\: (x-1) \:is\: a \:factor \:of\: p(x),$

$then \:p(1)\:=\:0$

$2(1)^2 + k(1) \:= \:0$

$⇒ 2+k\: = \:0$

$⇒ k\:= \:-2$

$Hence, \:the\: value \:of \:k \:is\: -2.$