find the value of k for each of the following quadratic equation so that they have two equal roots first 2 X square + kx + 3 is equal to zero second kx x minus 2 + 6 is equal to zero
nitthesh7:
pls make the ques clear
pls make the ques clear I can answer u
I make clear in another question plz check pic is there
fine
gotten
Answers
Answered by
12
♧♧♧HERE IS YOUR ANSWER♧♧♧
♤RULE♤
Let, a quadratic equation be :
ax² + bx + c = 0 .....(i)
This equation will have equal roots, when the discriminant is zero,
i.e., b² - 4ac = 0
♤SOLUTION♤
1)
Given :
2x² + kx + 3 = 0
Comparing it with (i), we get :
a = 2, b = k and c = 3.
So, applying the condition (b²-4ac=0) for equal roots, we write :
k² - 4.2.3 = 0
=> k² = 24
=> k = ± 2√6
2)
Given :
kx(x - 2) + 6 = 0
or, kx² - 2kx + 6 = 0
Comparing it with (i), we get :
a = k, b = -2k and c = 6.
So, applying the condition (b²-4ac=0) for equal roots, we write :
(-2k)² - 4.k.6 = 0
=> 4k² - 24k = 0
=> k(k-6) = 0
=> k = 0 and k = 6
⬆HOPE THIS HELPS YOU⬅
♤RULE♤
Let, a quadratic equation be :
ax² + bx + c = 0 .....(i)
This equation will have equal roots, when the discriminant is zero,
i.e., b² - 4ac = 0
♤SOLUTION♤
1)
Given :
2x² + kx + 3 = 0
Comparing it with (i), we get :
a = 2, b = k and c = 3.
So, applying the condition (b²-4ac=0) for equal roots, we write :
k² - 4.2.3 = 0
=> k² = 24
=> k = ± 2√6
2)
Given :
kx(x - 2) + 6 = 0
or, kx² - 2kx + 6 = 0
Comparing it with (i), we get :
a = k, b = -2k and c = 6.
So, applying the condition (b²-4ac=0) for equal roots, we write :
(-2k)² - 4.k.6 = 0
=> 4k² - 24k = 0
=> k(k-6) = 0
=> k = 0 and k = 6
⬆HOPE THIS HELPS YOU⬅
Similar questions