find the value of k for each of the following quadratic equation so that they have two equal roots kx²-10x+1=0
Answers
Answered by
0
Answer:
kx^2-10x+1=0
as the two roots are equal ,so, in the quadratic equation ax^2+bx+c=0
b^2-4ac=0
here b= -10
a=k
c=1
so,
100-4.k.1=0
=> 4k=100
=> k=100/4
=> k=25
so k=25
Answered by
1
Answer:
25
Step-by-step explanation:
for equal roots , we know
D = 0
=> b²-4ac=0
=> (-10)²-4(k)(1)=0
=> 100-4k=0
=>4k=100
=>k=25
therefore , the required value of k for the above quadratic equation to have equal roots is 25.
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