Math, asked by pputtabuddi, 2 months ago

find the value of k for each of the following quadratic equation so that they have two equal roots kx²-10x+1=0​

Answers

Answered by bagkakali
0

Answer:

kx^2-10x+1=0

as the two roots are equal ,so, in the quadratic equation ax^2+bx+c=0

b^2-4ac=0

here b= -10

a=k

c=1

so,

100-4.k.1=0

=> 4k=100

=> k=100/4

=> k=25

so k=25

Answered by hellomeae
1

Answer:

25

Step-by-step explanation:

for equal roots , we know

D = 0

=> b²-4ac=0

=> (-10)²-4(k)(1)=0

=> 100-4k=0

=>4k=100

=>k=25

therefore , the required value of k for the above quadratic equation to have equal roots is 25.

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