Question

Find the value of k for given equation so that they have equal root kx (x -2) +6=0 class 10 th

Answer 1

Hello...

Hope you'll be able to understand my solution...

kx(x-2)+6=0

Implies, kx^2-2kx+6=0. .....(1)

Now, let the roots be a and a.

Therefore, the factors are (x-a) and (x-a).

Hence, (x-a)(x-a) = x^2-ax-ax+a^2 = x^2-2ax+a^2.

Compare this with (1).

So, it can be found that the value of k is 1.

Thank you.

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