Question

find the value of k for infinitely many solutions.
2x-3y=k-3
x+y=k+3

Answer 1

Solution:

$for \: infinite \: no. \: of \: solution \\ \frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$
Now,

=>2/1= -3/1= k-3/k+3

=> 2/1= k-3/k+3

=> k-3= 2k+6

=> -k= 9

=> k = -9

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Hope it helps☺☺

#Amrit⭐

Answer 2

Hope it will help you