Question

Find the value of K for quadratic equation Kx^2+(2K+4)x+9=0.So that they have two equal roots

Answer 1

Answer:

The given equation can be written in the form of

k {x}^{2} - 2kx + 6 = 0

now it has equal roots that means The Discriminant is 0

D = 0

Also

{b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6

Hence the value of K is 6.

Answer 2

Answer:

use discriminant

Step-by-step explanation:

a=K , b=(2K+4) , c=9

now use

D= -b+-√b^2-4.a.c

do one for + and another for -