Find the value of k for quadratic equations 2xsqua+kx+3=0,so thta they have equal roots
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2x²+ kx + 3 =0
if roots are equal then alpha = beta,beta= alpha
Alpha + beta = - k /2
alpha + alpha = - k/2
2alpha = -k/2
alpha = -k /4
_______
alpha × beta = 3/2
alpha ² = 3/2
(-k/4)² = 3/2
k² /16 = 3/2
2k² = 48
k²= 24
k = √ 24
or
k is 4.8
or
k is 2√ 6
if roots are equal then alpha = beta,beta= alpha
Alpha + beta = - k /2
alpha + alpha = - k/2
2alpha = -k/2
alpha = -k /4
_______
alpha × beta = 3/2
alpha ² = 3/2
(-k/4)² = 3/2
k² /16 = 3/2
2k² = 48
k²= 24
k = √ 24
or
k is 4.8
or
k is 2√ 6
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