Find the value of k for the
equation 4xsquare + 4xk +
9=0 has equal roots.
Answers
Answered by
0
Answer:
Your answer is 12/3
Step-by-step explanation:
Given ,
4x^2+4xk+9=0
And given the roots of quadratic equation are equal.
So,
b^2-4ac=0
Where, a=4, b=4k, c=9
(4k) ^2-4(4) (9) =0
16k^2-144=0
16k^2=144
k^2=144/16
k=√144/16
K=12/4
Hope this is useful to you
Answered by
0
Answer:
k= ±3
Step-by-step explanation:
α+β= -b/a ---1
α*β= c/a ---2
as, roots are equal α=β
from 1,
2α= (-4k)/4
α= -k/2
from 2,
α²=9/4
squaring 1 we get α²= k²/4
comparing 1 and 2
(k²/4)=(9/4)
we get k=√9
k=±3
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