Question

Find the value of k for the following quadratic equation, so that it should have equal roots: kx²+ 6x + 1 = 0 *​

Answer 1

Answer :

k = 9

Step-by-step explanation :

Given quadratic equation,

kx² + 6x + 1 = 0

It is of the form ax² + bx + c = 0

=> a = k, b = 6, c = 1

CONDITION : it should have equal roots

So, discriminant, D = 0

           $\boxed{D=b^2-4ac}$

            $6^2-4(k)(1) =0\\\\ 36-4k=0\\\\ 4k=36 \\\\ k=36/4 \\\\ k=9$