Question

Find the value of k for the following quadratic equation, so that it should have equal roots: kx²+ 6x + 1 = 0 ​

Answer 1

Answer:

The value of equation is 9.

Answer 2

$Compare \: given \: Quadratic \: equation \\kx^{2} + 6x + 1 = 0 \: with \: ax^{2}+bx + c = 0, \\we \:get$

$a = k , \: b = 6 \: and \: c = 1$

$\pink{ Discreminant ( \triangle ) = 0 }$

$\blue{ ( Given \: roots \: are \: equal . )}$

$\implies b^{2} - 4ac = 0$

$\implies 6^{2} - 4\times k \times 1 = 0$

$\implies -4k =- 6^{2}$

$\implies k = \frac{ -36}{-4}$

$\implies k = 9$

Therefore.,

$\red{ Value \: of \: k } \green { = 9 }$

••♪