Question

Find the value of K for the whicX=-2is a root of the quadratic equation kx2+x-6=0.

Answer 1

Step-by-step explanation:

Quadratic equation has equal roots then b2−4ac=0

Given that kx2−2kx+6=0

Here a=k,b=−2k and c=6

Now, (−2k)2−4×k×6=0

⇒4k2−24k=0

⇒4k(k−6)=0

⇒k=0 or k=6