In an ap consists of 43 terms, if the sum of 5 middle most term is 195, then sum of ap is ?
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Step-by-step explanation:
For elements in AP..
a1 = a
a2 = a + d
a3 = a + 2d
a4 = a + 3d
...
if the sum of 5 middle most term is 195.
Middle term in AP - (43 + 1)/2 = 22
a20 + a21 + a22 + a23 + a24 = 195
(a + 19d) + (a + 20d) + (a + 21d) + (a + 22d) + (a + 23d) = 195
5a + 19d + 20d + 21d + 22d + 23d = 195
5a + 105 d = 195
Therefore, a + 21 d = 39 --- (1)
Now sum of ap :- a1 + a2 + a3.. a43
= a + (a+d) + (a+2d) + .... (a+ 42d)
= 43a + (42.43/2)d
= 43a + 903d
= 43 ( a + 21d)
Substituting from 1 we get,
= 43 x 39 = 1677
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