Find the value of k for which (−2,−3) is a solution of kx−2y=0. Find two more solutionsof this equation.
Answers
Answered by
1
Step-by-step explanation:
x = -2 ; y = -3
k(-2) - 2(-3) = 0
-2k + 6 = 0
2k = 6
k = 3
Two more solutions are :
1) (2,3)
2) (4,6)
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Answered by
0
Step-by-step explanation:
-2=0 : =-2 =-3
(-2)-2(-3)=0
-2+6=0
-2=-6
=-6/-2
= 3.
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