Question

Find the value of k for which 2 x square + kx + 8 has equal value

Answer 1

Answer

It is given in the question that $2x^2 + kx + 8 = 0$i.e., it has equal roots.

So, According to the question,

we get that ,

a = 2

b = k

c = 8

We will find the value of k by puuting the values in quadratic formula,

Quadratic formula = $\bold{b^2 - 4ac}$

$b^2 - 4ac = 0$

putting the values in the formula,

$k^2 - 4\times 2\times 8 = 0$

$k^2 - 64 = 0$

$k^2 = 64$

$k = \pm\sqrt{64}$

$k = \pm 8$

Therefore, for the value of k as 8 we will get 0 as remainder.

$\boxed{\bf{k =\pm 8}}$