Question

Find the value of K for which 2x+2y+2=0 and4x+KY+8=0 will have unique solution

Answer 1

For unique solution =

a1/a2 is not equal to b1/b2

=2/4 is not equal to 2/k

k must not be equal to 4

Answer 2

2x+2y+2=0

4x+ky+8=0

for unique solution

a1/a2≠b1/b2

2/4≠2/k≠2/8

⇒2k≠8  ⇒ k≠4

and also , 2k≠16 ⇒ k≠8