Question

FIND THE VALUE OF K FOR WHICH (8,1 ), (K,-4), (2,-5) POINTS ARE COLLINEAR​

Answer 1

Step-by-step explanation:

for points to be collinear, area=0

using area of triangle formula,

1/2[8(-4+5)+k(-5-1)+2(1+4)]=0

-32+40-6k+10=0

18-6k=0

6k=18

k=3

Answer 2

Answer:

3

Step-by-step explanation:

when the points are collinear then the area formed by them = 0

1/2 [x1(y2-y3)+x2(y3-y1)+x3(y1-y2)] = 0

1/2 *[8(-4-(-5)) + k(-5 - 1) + 2{1- (-4)} ] = 0

1/2* [8 - 6k + 10] = 0

6k = 18 => k = 3