find the value of k for which is X square + kx-4=0, x=-4
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Answered by
1
Hey
Here is your answer,
X^2 + kx - 4 =0
Substitute the value of x = -4 in the equation to find the value of k,
(-4)^2 + (-4)k -4=0
16-4k-4=0
12-4k=0
-4k=-12
k=-12/-4
k=3
Hope it helps you!
Here is your answer,
X^2 + kx - 4 =0
Substitute the value of x = -4 in the equation to find the value of k,
(-4)^2 + (-4)k -4=0
16-4k-4=0
12-4k=0
-4k=-12
k=-12/-4
k=3
Hope it helps you!
Answered by
0
what is k in the question? is it alebra
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