Math, asked by sarahfatima4484, 1 year ago

Find the value of k for which kx+3y=k+2 and 12 x+ky=k has no solution

Answers

Answered by mdmd

1

for no solution
a1/a2 is not = to b1/b2
k/12 is not =3/k
k^2 = 36
k = under root 36

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