find the value of k for which of the following system of equation has a unique solution
4x-5y=k,2x-3y=12
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The given system of equations are 4x - 5y = k ⇒ 4x - 5y - k = 0 ….(i) And, 2x - 3y = 12 ⇒2x - 3y - 12 = 0 …(ii) These equations are of the following form: a1x+b1y+c1 = 0, a2x+b2y+c2 = 0 Here, a1 = 4, b1= -5, c1 = -k and a2 = 2, b2 = -3, c2 = -12 For a unique solution, we must have: Thus, for all real values of k, the given system of equations will have a unique solution.Read more on Sarthaks.com - https://www.sarthaks.com/131775/find-the-value-of-k-for-which-the-system-of-equations-has-a-unique-solution-4x-5y-k-2x-3y-12
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