find the value of k , for which one root of quadratic equation k-14x+8=0 is six timesthe other
Answers
Answered by
1
Let roots be a and b
Given, a = 6b
if a and b are roots then equation will be (x -a)(x -b) =0
(x -a)(x -b) =0
x^2 - (a+b)x + ab =0
x^2 - (6b +b)x + 6b^2 =0
x^2- 7bx +6b^2 =0
Given, kx^2 -14x +8 =0
7b =14/kb =2/k
b^2 = 4/k^2 ----------------- (i)
and 6b^2 =8/k
b^2 =4/3k ---------------- (ii)
from (i) and(ii)
4/k^2 = 4/3k
k =3.
Hope this helps!
Given, a = 6b
if a and b are roots then equation will be (x -a)(x -b) =0
(x -a)(x -b) =0
x^2 - (a+b)x + ab =0
x^2 - (6b +b)x + 6b^2 =0
x^2- 7bx +6b^2 =0
Given, kx^2 -14x +8 =0
7b =14/kb =2/k
b^2 = 4/k^2 ----------------- (i)
and 6b^2 =8/k
b^2 =4/3k ---------------- (ii)
from (i) and(ii)
4/k^2 = 4/3k
k =3.
Hope this helps!
Similar questions
Computer Science,
7 months ago
Math,
7 months ago
English,
7 months ago
Political Science,
1 year ago
Math,
1 year ago
Science,
1 year ago