Find the value of k for which one root of the quadratic equation kXsquare-14x+8=0 is 2.
Answers
Answered by
2
wait I am solving quadratic equation
and is
k=5
and is
k=5
Attachments:
Answered by
1
kx² - 14x + 8 = 0
pu + 2 = x
k (2)² - 14 (2) - 18 = 0
4k - 28 + 8 = 0
4k - 20 = 0
4k = 20
k = 20 ÷ 4 = 5
k = 5
pu + 2 = x
k (2)² - 14 (2) - 18 = 0
4k - 28 + 8 = 0
4k - 20 = 0
4k = 20
k = 20 ÷ 4 = 5
k = 5
Similar questions