Find the value of k for which one root of the quadratic equation kx2-14x+8=0 is 2
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k4-28+8=0
4k=20
k=20/5
k=5
4k=20
k=20/5
k=5
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Answer:
Step-by-step explanation:
2k -14x+8 =0
2k=14x-8
k= 14x-8-2
K= 14x-10
x=14/10
k=7/5
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