Find the value of k , for which one root of the quadratic equatiom kx^2-14x+8=0 is 2
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Answer:
K=5
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Take x=2
》kx^2-14x+8=0
》k (2)^2-14 (2)+8=0
》k 4-28+8=0
》4k-28=0
》4k=28
》k=28÷4
》k=7
Hope it will help you.
》kx^2-14x+8=0
》k (2)^2-14 (2)+8=0
》k 4-28+8=0
》4k-28=0
》4k=28
》k=28÷4
》k=7
Hope it will help you.
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