Question

Find the value of k, for which one root of the quadratic equation kx2

-14x+8 = 0 is 2.​

Answer 1

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Answer 2

Answer: k= 5

Step-by-step explanation:

Given,one root = 2

kX^2 - 14X + 8 = 0

Substitute '2' in place of X

k*2^2 - 14*2 + 8 = 0

4k - 28 + 8 = 0

4k - 20 = 0

4k = 20

k = 20/4 = 5

Answer 3

Let x be 2 ,then

K(2)^2-14(2)+8=0

K4-28+8=0

K4=20

K=5