is it necessary that action and reaction produce acceleration of the same magnitude???
Thakur234:
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Remember that force = mass * acceleration (commonly expressed as F=ma).
Imagine here that we have a solution to a multiplication problem that looks as follows:
12 = x*y
x and y could be 6 and 2, or 4 and 3, or 12 and 1, or any number of combinations of fractions. Yet, the solution in each case is 12.
Just like this problem, the force (F) will also be equal in the solution for both bodies meeting in the reaction. What will be different is the combination of numbers for mass (m) and acceleration (a). Just like a larger x value (6) in our equation necessitated a smaller y value (2) in order to make 12, an item with larger mass will require a lower acceleration in order to create equivalent force.
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hope this helps
Remember that force = mass * acceleration (commonly expressed as F=ma).
Imagine here that we have a solution to a multiplication problem that looks as follows:
12 = x*y
x and y could be 6 and 2, or 4 and 3, or 12 and 1, or any number of combinations of fractions. Yet, the solution in each case is 12.
Just like this problem, the force (F) will also be equal in the solution for both bodies meeting in the reaction. What will be different is the combination of numbers for mass (m) and acceleration (a). Just like a larger x value (6) in our equation necessitated a smaller y value (2) in order to make 12, an item with larger mass will require a lower acceleration in order to create equivalent force.
◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆◆
hope this helps
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