Question

Find the value of k,for which one root of the quadrtic equation kx²-14x+8=0is six times the other.

Answer 1

Answer:

Step-by-step explanation:

a , b roots and a = 6b

a + b = 14 / k , ab = 8 / k

a + b = 14 / k ---> 6b + b = 14 / k

---> 7b = 14 / k ---> b = 2 / k

---> a = 12 / k ---> ab = 24 / k^2.

we have :

ab = ab ---> 24 / k^2 = 8 / k

---> 3 / k = 1 ---> k = 3.