Find the value of k,for which one root of the quadrtic equation kx²-14x+8=0is six times the other.
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Step-by-step explanation:
a , b roots and a = 6b
a + b = 14 / k , ab = 8 / k
a + b = 14 / k ---> 6b + b = 14 / k
---> 7b = 14 / k ---> b = 2 / k
---> a = 12 / k ---> ab = 24 / k^2.
we have :
ab = ab ---> 24 / k^2 = 8 / k
---> 3 / k = 1 ---> k = 3.
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