Question

find the value of k for which quadratic equation have equal roots kx(x-2)+6=0​

Answer 1

Answer:

24

Step-by-step explanation:

kx^2-kx+6=0

b^2-4ac=0        (as roots are given equal)

(-k)^2-4*k*6=0

k^2-24k=0

k^2=24k

k=24