Question

.
find the value of k for which roots of quadeatic eq.
kx2 +2x+3=0​

Answer 1

Answer:

kx²+2x+3

a= k, b=2, c=3

D= b²- 4ac

= (2)² - 4(k)(3)

= 4 - 12k

As the roots are equal :-

4-12k = 0

12k = 4

k = 4/12

k = 1/3

Hope it helps...

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