Question

find the value of k for which th area formed the triangle with vertices A(k,-2k) B (-2,6) C(-3,1) is 5 sq units​

Answer 1

Step-by-step explanation:

ANSWER

Area of a triangle with vertices (x

1

,y

1

) ; (x

2

,y

2

) and (x

3

,y

3

) is

∣

∣

∣

∣

2

x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)

∣

∣

∣

∣

Hence, area of the triangle with given vertices

∣

∣

∣

∣

2

k(6−1)−2(1−2k)+3(2k−6)

∣

∣

∣

∣

=20

=>

∣

∣

∣

2

6k−k−2+4k+6k−18

∣

∣

∣

=20

∣

∣

∣

2

15k−20

∣

∣

∣

=20

∣15k−20∣=40

15k−20=40

15k=60

k=4