Question

Find the value of k for which the eq 9x^2-3kx+k=0 has equal root.

Answer 1

k=9 hoga my friend any doubt

Answer 2

HERE IS YOUR ANSWER....⬇⬇

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Given,

The equation :


$9x {}^{2} - 3kx + k = 0$

Here,

$a = 9 \\ b = - 3k \\ c = k$

If the equation has two equal root, then

$b {}^{2} - 4ac = 0 \: \: \: - - - - > (1)$

By putting the values of a , b and c in eq.(1) ,

$b {}^{2} - 4ac = 0 \\ \\ = > ( - 3k) {}^{2} - 4 \times 9 \times k = 0 \\ \\ = > 9k {}^{2} - 36k = 0 \\ \\ = > 9k \: (k- 4) = 0 \\ \\ = > k - 4 = 0 \\ \\ = > k = 4$

•°• Value of K = 4

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