Question

Find the value of k for which the equation 2X^2 + KX+ 3 = 0 has two equal roots

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$for \: having \: equal \: roots \: \\ {b}^{2} - 4ac = 0 \\ {k}^{2} - 4 \times 2 \times 3 = 0 \\ {k}^{2} - 24 = 0 \\ {k}^{2} = 24 \\ k = \sqrt{24} \: and \: - \sqrt{24} \\ k = 2 \sqrt{6} \: and \: - 2 \sqrt{6}$

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