find the value of k for which the equation 2xsq+KX+3=0
Anonymous:
Improper Question
noo its of my question paper
it was my exam and it was one of the questions
pls rewrite the question..
ok
find the value of k for which the equation 2xsq +kx+3=0 has equal roots
sq means ??
square
it doesnt has the symbol of square
Answers
Answered by
1
discriminant = 0
k^2 - 4.2.3 = 0
k = √24 = 2√6
k^2 - 4.2.3 = 0
k = √24 = 2√6
r u sure ??
yes
noo
actually m not understanding the que properly what is the actual equation ????
yes dear uranswer is ryt
2x^2plus kx plus 3
ha i got it when sujeet solved it
hmm
Answered by
2
HEY THERE!!!
Question;-find the value of k for which the equation 2x²+KX+3=0
Method of Solution;-
Given Equation;-
2x²+kx+3=0
Find Discriminant Of Equation;-
We know that D=b²-4ac
For Real and Equal must be 0
=> b²-4ac
=>(k)²-4.2.3=0
=> k²-24=0
=> k²=24
=> k=√24
=> k=√6×4
=> k=±2√6
Or, K=-2√6
Hence, ±2√6 value of k
Question;-find the value of k for which the equation 2x²+KX+3=0
Method of Solution;-
Given Equation;-
2x²+kx+3=0
Find Discriminant Of Equation;-
We know that D=b²-4ac
For Real and Equal must be 0
=> b²-4ac
=>(k)²-4.2.3=0
=> k²-24=0
=> k²=24
=> k=√24
=> k=√6×4
=> k=±2√6
Or, K=-2√6
Hence, ±2√6 value of k
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