Math, asked by Poojithisinghdc, 1 year ago

Find the value of k for which the equation kx[x-2]+6=0 has equal roots.

Answers

Answered by Rose2110
6
B^2-4ac=0
B=-2k
A=K
C=6

Therefore,
4k^2- 24k=0
4k^2=24k
4k=24
K=6
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