find the value of k for which the equation
![(k + 1)x {}^{2} - 2(k - 1)x + 1 = 0 (k + 1)x {}^{2} - 2(k - 1)x + 1 = 0](https://tex.z-dn.net/?f=%28k+%2B+1%29x+%7B%7D%5E%7B2%7D++-+2%28k+-+1%29x+%2B+1+%3D+0)
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D=0 because the equation has equal and real root
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