Math, asked by anmol200005, 8 months ago

find the value of k for which the equation x^2+k(2x+k-1)+2=0 gas real and distinct roots​

Answers

Answered by tanika
1

Answer:

Step-by-step explanation:

If the quadratic equation has real root ,it means that the discriminant equals 0 or if you plot it graphically it will touch the x axis at one point.

D=0

b^2 -4ac =0

K^2 - 4(k-1)=0

K^2 -4k +4=0

(K-2)^2 =0

K=2

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