Question

Find the value of k for which the equation x²+2(k+1)x+k²=0 has equal roots​

Answer 1

Answer:

k = -1/2 or -0.5

Step-by-step explanation:

ax² + bx + c = 0

In case of equal roots D = 0 => b² - 4ac = 0

In given euation :  x²+2(k+1)x+k²=0

b = 2(k+1) ;  a = 1 ; c = k²

so, D = 0

(2(k+1))²-4k² = 0 => 4( k²+2k+1) - 4k²

=> 4k²+8k+4 - 4k² =0

=> 8k + 4 = 0 => k = -1/2

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