Question

Find the value of k for which the following points are colinear (7,-2) (5,1) (3,k)

Answer 1

Answer:

Step-by-step explanation:

(i) For collinear points, area of triangle formed by them is zero. Therefore, for points (7, -2) (5, 1), and (3, k), area = 0 1/2 [7 { 1- k} + 5(k-(-2)) + 3{(-2) + 1}] = 0 7 - 7k + 5k +10 -9 = 0 -2k + 8 = 0 k = 4 (ii) For collinear points, area of triangle formed by them is zero. Therefore, for points (8, 1), (k, - 4), and (2, - 5), area = 0 1/2 [8 { -4- (-5)} + k{(-5)-(1)} + 2{1 -(-4)}] = 0 8 - 6k + 10 = 0 6k = 18 k = 3Read more on Sarthaks.com - https://www.sarthaks.com/2442/in-each-of-the-following-find-the-value-of-k-for-which-the-points-are-collinear-i-7-2-5-1-3-k-ii-8-1

Answer 2

Answer:

Step-by-step explanation: