Question

find the value of k for which the following quadratic equation has two equal roots
2x^+kx+3=0​

Answer 1

Step-by-step explanation:

given equation is :-

2x+kx+3=0

a=2

b=k

c=3

D=b^2-4ac

D= (k) ^2 -4(2)(3)

D = k^2-24

For equal roots, discriminant

k^2-24=0

k^2=24

k =+√24

k = +2√6

or

k=-√24

k=-2√6

Hence,

For, k=+2√6 are equal roots.

Hence, proved ......!

Hope it helps you......

Answer 2

Answer:

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