Find the value of k for which the following system of equations has no solution:
2 x - ky + 3 = 0 and 3x +2y-1 =0
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Answer:
-4/3 = k
Step-by-step explanation:
2x-ky+3=0
3x+2y-1=0
On comparing the equations wit their standard forms
we get ,
a1=2 , b1=-k , c1=3 , a2=3 , b2=2 , c2=-1
For no solutions
a1/a2 = b1/b2 not= c1/c2
now put the values
2/3 = -k/2 not= 3/-1
from a1/a2 = b1/b2
2/3 = -k/2
on taking 1/2 from RHS to LHS and then solving we get
4/3 = -k
-4/3 = k
(only if the school says to then do the rest)
if you have to show not= , then,
from b1/b2 not= c1/c2
-k/2 not=3/-1
on taking 1/2 from LHS to RHS and then solving we get
-k not= 6/-1
-k not= -6
k not= 6
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