Question

Find the value of k for which the following system of equations be inconsistent 2x + ky + 2 = 0. , Kx + 8y + 3k = 0

Answer 1

Hey friend,

Here is the solution :-

Here, system of equations is inconsistent, therefore :-

A1/A2 = B1/B2 ≠ C1/C2

Here, A1 = 2 B1 = k C1 = 2

A2 = k B2 = 8 C2 = 3

$\frac{a1}{a2} = \frac{2}{k} \: \: \: \: \frac{b1}{b2} = \frac{k}{8} \\ \\ \\ \\ \frac{a1}{a2} = \frac{b1}{b2} = \frac{2}{k} = \frac{k}{8} \\ \\ \frac{2}{k} = \frac{k}{8} \: \: \: \: now \: by \: cross \: multiplication : - \\ \\ k \times k = 8 \times 2 \\ \\ {k}^{2} = 16 \\ \\ k = \sqrt{16} \\ k = 4$

So, we get k = 4

✨I hope this will help you....✨