Find the minimum or maximum y-value for f(x) = 3x^2 + 12x + 4
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f(x)=3x^2+12x+4
diffrentiating w.r t.x
f^1(x)=6x+12
given y-value so x=0
f^1(x)=12which is greaté than 0
i.e function is minimum
diffrentiating w.r t.x
f^1(x)=6x+12
given y-value so x=0
f^1(x)=12which is greaté than 0
i.e function is minimum
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