Question

find the value of k for which the following system of equations has a unique solution a) kx+2y=5,3x+y=1​

Answer 1

kx +2y=5

3x+y=1

k(3)=2

k=2/3

and

-5(1)=k(3)

k=-5/3

Answer 2

Multiply eq 2 with 2

6x+2y=2

Now subtract eq 2 from eq 1

Kx+2y=5

-(6x+2y=2)

(K-6)x=3

Neglect x

K-6=3

K=9

Hope this may help u.....