Question

find the value of k for which the following terms are in AP K + 2, 4 k - 6, 3 k - 2​

Answer 1

Answer:

k = 3

Step-by-step explanation:

Given Series: k+2, 4k - 6, 3k -2

According to AP, the common difference is same among all the terms.

⇒ 4k - 6 - ( k + 2 ) = 3k - 2 - ( 4k - 6 )

⇒ 4k - 6 - k - 2 = 3k - 2 - 4k + 6

⇒ 3k - 8 = -k + 4

⇒ 3k + k = 4 + 8

⇒ 4k = 12

⇒ k = 12/4 = 3

Therefore the value of k is 3.

Hope it helped !!

Answer 2

Solutions:

4k - 6 - (k + 2) = 3k - 2 - (4k - 6)

4k - 6 - k - 2 = 3k - 2 - 4k + 6

3k + k = -k + 4

4k = 12

k = 3

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