Question

Find the value of K for which the given quadratic equation has equal real roots: kx^2-6x-2=0

Answer 1

Answer:

kx²-6x-2

THE EQUATION HAS REAL ROOTS

therefore,

D>0

b²- 4ac > 0

(-6)² - 4(k)(-2) > 0

36 + 8k > 0

8k > -36

k > -36/8

k > 4.5

approx. 5

HOPE THIS HELPED YOU!

Answer 2

Answer:

k = - 9/4

Step-by-step explanation:

The condition for a quadratic equation

ax^2 + bx + c = 0

to have equal roots, is

b^2 − 4ac = 0

For the given equation

kx^2 - 6x − 2 = 0

b^2 − 4ac = (−6)^2 - 4k(−2) = 0

36 + 8k = 0

8k = -36

k = - 36/8

k = - 9/4