Question

Find the value of k for which the pair of equations kx-y=2 and 6x-2y=3 will have no solution

Answer 1

Heya Mate!!!

Given system of equations are

6x - 2y = 3

6x - 2y - 3 = 0 ----( 1 )

kx - y = 2

kx - y - 2 = 0 ----( 2 )

Compare above equations with

a1 x + b1 y + c1 = 0 and

a2 x + b2 y + c2 = 0 , we get

a1 = 6 , b1 = -2 , c1 = -3 ;

a2 = k , b2 = -1 , c2 = -2 ;

Now ,

a1/a2 ≠ b1/b2



6/k ≠ ( -2 )/( -1 )

6/k ≠ 2

k/6 ≠ 1/2

k ≠ 6/2

k ≠ 3


Hope The Ans Will Help u

Be happy Be Brainly

Answer 2

KX - Y = 2



KX - Y - 2 = 0 -------------(1)



And,


6X - 2Y = 3


6X - 2Y - 3 = 0 ------------(2)





These equation are of the form A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0 , Where


A1 = K , B1 = -1 and C1 = -2



And,

A2 = 6 , B2 = -2 and C2 = -3





A1/A2 = K/6 and B1/B2 = -1/2 = 1/2.




For no solution we must have ,


A1/A2 # B1/B2 [ Where # stands for not equal ]




K/6 # 1/2




2K # 6


K # 3.




Hence,

K has all real value other than 3.